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Write an algebraic expression for the area of a regular hexagon with: a. A perimeter of 4x units and an apothem of 6 units: b. A perimeter of (6x+12) units and an apothem of 4 units:

Question

Write an algebraic expression for the area of a regular hexagon with: a. A perimeter of 4x units and an apothem of 6 units: b. A perimeter of (6x+12) units and an apothem of 4 units:

Write an algebraic expression for the area of a regular hexagon with:
a. A perimeter of 4x units and an apothem of 6 units:
b. A perimeter of (6x+12) units and an apothem of 4 units:

Solution

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RileyMaster · Tutor for 5 years

Answer

### a. $12x$ square units<br />### b. $(12x + 24)$ square units

Explain

## Step 1: Area of a regular polygon<br />### The area of a regular polygon is given by the formula $A = \frac{1}{2} \times \text{perimeter} \times \text{apothem}$.<br /><br />## Step 2: Area of the hexagon (a)<br />### Substitute the given perimeter $4x$ and apothem $6$ into the area formula: $A = \frac{1}{2} \times 4x \times 6 = 12x$.<br /><br />## Step 3: Area of the hexagon (b)<br />### Substitute the given perimeter $(6x+12)$ and apothem $4$ into the area formula: $A = \frac{1}{2} \times (6x+12) \times 4 = 2(6x+12) = 12x + 24$.
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