Which equation completes the square to create an equivalent equation in the form of (x-p)^2=q x^2-6x+6=0 Show your work here (x-6)^2=6 (x-3)^2=3 (x)^2=20 (x-3)^2=-3

## Step 1: Rewrite the equation<br />### Move the constant term to the right side of the equation.<br />$x^2 - 6x = -6$<br /><br />## Step 2: Complete the square<br />### Add $(\frac{b}{2})^2$ to both sides of the equation. Here, $b = -6$, so $(\frac{b}{2})^2 = (\frac{-6}{2})^2 = (-3)^2 = 9$.<br />$x^2 - 6x + 9 = -6 + 9$<br /><br />## Step 3: Simplify<br />### Simplify both sides of the equation.<br />$x^2 - 6x + 9 = 3$<br /><br />## Step 4: Factor the left side<br />### Factor the left side as a perfect square.<br />$(x-3)^2 = 3$