600=(40-2 x)(30-2 x) arrow Factor

## Step 1: Expand the equation<br />### Expand the right side of the equation using the FOIL method: $(40-2x)(30-2x) = 1200 - 80x - 60x + 4x^2 = 4x^2 - 140x + 1200$. So, the equation becomes $600 = 4x^2 - 140x + 1200$.<br /><br />## Step 2: Simplify the equation<br />### Subtract 600 from both sides of the equation to set it equal to zero: $0 = 4x^2 - 140x + 600$.<br /><br />## Step 3: Divide by the greatest common factor<br />### Divide the entire equation by the greatest common factor, which is 4: $0 = x^2 - 35x + 150$.<br /><br />## Step 4: Factor the quadratic equation<br />### Find two numbers that multiply to 150 and add up to -35. These numbers are -30 and -5. Therefore, the factored form is $(x - 30)(x - 5) = 0$.