An experiment is conducted with 16 number cubes each with faces numbered 1 through 6. All the cubes are tossed and any cube that lands with a I facing up is removed. This process is repeated with the remaining cubes and continues for x tosses. Which equation represents y.the expected ted number of cubes remaining after x tosses? A. y=16((1)/(5))^x B. y=16((1)/(6))^x c y=16((4)/(5))^x D y=16((5)/(6))^x

Here's how to determine the correct equation:<br /><br />* **Probability of a cube remaining after one toss:** A cube remains if it shows any number *other* than 1. There are 5 such outcomes (2, 3, 4, 5, 6) out of 6 possible outcomes. So the probability of a cube remaining is 5/6.<br /><br />* **Expected number remaining after one toss:** With 16 cubes initially, the expected number remaining after one toss is 16 * (5/6).<br /><br />* **Expected number remaining after x tosses:** After each toss, the expected number remaining is multiplied by the probability of a single cube remaining (5/6). Therefore, after *x* tosses, the expected number remaining is 16 * (5/6) * (5/6) * ... * (5/6) (x times). This can be written as 16 * (5/6)^x.<br /><br />Therefore, the correct answer is **D. y = 16(5/6)^x**<br />