Section 2: Communication Directions: Indicate whether the statement is true or false. If false, change the identified word or phrase to make the statement true. 9. (1 point) An angle in standard position has an initial arm located on the x-axis. 10. (1 point) The reciprocal trigonometric ratios are defined as cscTheta =(r)/(y),secTheta =(r)/(x) , and cotTheta =(y)/(x) 11. (1 point) Stretching sinusidal functions horizontally affects the amplitude of the function. 12. (1 point) The graph of y=cos((x)/(6)) has a period of 60 degrees. 13. (1 point) The graph of y=cosx is translated 40 degrees left. The equation of the translated function then is y=cosx+40 14. (1 point) The range of y=-2sinx-1 is -3leqslant yleqslant -1 15. (1 point) The domain of the function y=tanx is xin R,xneq pm 90,pm 270,ldots 16. (1 point) The period of y=tan(kx) is (360^circ )/(k)

9. (1 point) **True**. An angle in standard position *does* have its initial arm located on the positive x-axis.<br /><br />10. (1 point) **False**. The reciprocal trigonometric ratios are defined as $csc\Theta =\frac {r}{y},sec\Theta =\frac {r}{x}$ , and $cot\Theta =\frac {x}{y}$. Change $\frac{y}{x}$ to $\frac{x}{y}$ for cotangent.<br /><br />11. (1 point) **False**. Stretching sinusoidal functions horizontally affects the *period* of the function.<br /><br />12. (1 point) **False**. The graph of $y=cos(\frac {x}{6})$ has a period of $\frac{360^{\circ}}{1/6} = 2160$ degrees or $12\pi$ radians. Change 60 degrees to 2160 degrees (or $12\pi$ radians).<br /><br />13. (1 point) **False**. The graph of $y=cosx$ is translated 40 degrees left. The equation of the translated function is $y=cos(x+40)$. The equation should be $y = cos(x + 40)$.<br /><br />14. (1 point) **False**. The range of $y=-2sinx-1$ is $-3\leqslant y\leqslant 1$. Change -1 to 1. The sine function oscillates between -1 and 1. Multiplying by -2 gives a range of -2 to 2. Subtracting 1 shifts the range down to -3 to 1.<br /><br />15. (1 point) **False**. The domain of the function $y=tanx$ is $\{ x\in R,x\neq \pm 90^{\circ},\pm 270^{\circ},\ldots \} $ or in radians, $\{x \in \mathbb{R} | x \neq \frac{(2n+1)\pi}{2}, n \in \mathbb{Z}\}$. The degree symbol is missing.<br /><br />16. (1 point) **True**. The period of $y=tan(kx)$ is $\frac {180^{\circ }}{k}$ or $\frac{\pi}{k}$ radians. Since the standard period of the tangent function is 180 degrees or $\pi$ radians.<br />