6. A Cyclops that is resistant to pesticides and has smooth antennae is crossed with one that is heterozygous for both traits. Show the genotypes of the parents. [ ( RRSS ) times ( RrSs ) ] 7. Set up a punnett square for the cross. & & & & & & & & & & & &

## Step 1: Understanding the Genotypes of the Parents<br />### The problem states that one Cyclops is resistant to pesticides and has smooth antennae, with a genotype of \( RRSS \). This means it is homozygous dominant for both traits. The other Cyclops is heterozygous for both traits, with a genotype of \( RrSs \).<br /><br />## Step 2: Determining Possible Gametes<br />### For the \( RRSS \) parent, the only possible gamete is \( RS \) because it is homozygous for both traits.<br />### For the \( RrSs \) parent, the possible gametes are \( RS, Rs, rS, \) and \( rs \), as each allele can independently assort.<br /><br />## Step 3: Setting Up the Punnett Square<br />### A Punnett square is used to predict the genotypes of offspring from a genetic cross. Since one parent can produce only one type of gamete (\( RS \)), and the other can produce four types (\( RS, Rs, rS, rs \)), the Punnett square will have one row for the \( RRSS \) parent's gamete and four columns for the \( RrSs \) parent's gametes.<br /><br />\[<br />\begin{array}{|c|c|c|c|c|}<br />\hline<br /> & RS & Rs & rS & rs \\<br />\hline<br />RS & RRSS & RRSs & RrSS & RrSs \\<br />\hline<br />\end{array}<br />\]<br /><br />### Each cell in the table represents the combination of alleles from the gametes of each parent.