Question 2(Multiple Choice Worth 2 points) (01.06 MC) Simplify r^38 -1 -i 1

## Step 1: Simplify $i^{38}$ using the cycle of powers of $i$<br />### The powers of $i$ repeat in a cycle of 4: $i^1 = i$, $i^2 = -1$, $i^3 = -i$, $i^4 = 1$. To simplify $i^{38}$, we find the remainder when 38 is divided by 4. $38 \div 4 = 9$ with a remainder of 2. Therefore, $i^{38}$ is equivalent to $i^2$.<br />## Step 2: Evaluate $i^2$<br />### Since $i^2 = -1$ by definition, $i^{38} = i^2 = -1$.