Question
A women of blood type AB (1^Avert ^B) has a child with a man of blood type AB ( ") as well. What are the chances of the first child being blood type B? What are the chances of blood type O? 25% ,25% 100% ,0% 25% ,0% 0% ,0% 50% ,50%
Solution
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RosalieMaster · Tutor for 5 years
Answer
Here's how to determine the blood type probabilities for the child:<br /><br />**Understanding Blood Type Inheritance**<br /><br />* **A and B are codominant:** If someone has both A and B alleles, they have blood type AB.<br />* **O is recessive:** Someone needs two O alleles to have blood type O.<br /><br />**Parent Genotypes**<br /><br />* Mother: AB (I<sup>A</sup>I<sup>B</sup>)<br />* Father: AB (I<sup>A</sup>I<sup>B</sup>)<br /><br />**Punnett Square**<br /><br />A Punnett square helps visualize the possible combinations of alleles the child can inherit:<br /><br />| | I<sup>A</sup> | I<sup>B</sup> |<br />|-------|--------|--------|<br />| I<sup>A</sup> | I<sup>A</sup>I<sup>A</sup> | I<sup>A</sup>I<sup>B</sup> |<br />| I<sup>B</sup> | I<sup>A</sup>I<sup>B</sup> | I<sup>B</sup>I<sup>B</sup> |<br /><br />**Possible Child Genotypes and Phenotypes (Blood Types)**<br /><br />* I<sup>A</sup>I<sup>A</sup>: Blood type A<br />* I<sup>A</sup>I<sup>B</sup>: Blood type AB<br />* I<sup>B</sup>I<sup>B</sup>: Blood type B<br /><br />**Probabilities**<br /><br />* **Blood type A:** 1 out of 4 possibilities (25%)<br />* **Blood type AB:** 2 out of 4 possibilities (50%)<br />* **Blood type B:** 1 out of 4 possibilities (25%)<br />* **Blood type O:** 0 out of 4 possibilities (0%)<br /><br />**Answer**<br /><br />The correct answer is $\boxed{25\%, 0\%}$. There is a 25% chance the child will have blood type B and a 0% chance the child will have blood type O.<br />
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