For each value of w , determine whether it is a solution to 6-4 w=14 . multirow(2)(}{ w ) & multicolumn(2)(|c|)( Is it a solution? ) cline ( 2 - 3 ) & Yes & No -5 & & -10 & & 7 & & 4 & &

## Step 1: Understand the equation<br />### The given equation is \(6 - 4w = 14\). We need to determine if each value of \(w\) satisfies this equation.<br /><br />## Step 2: Solve for \(w\)<br />### To find the solution, we solve the equation for \(w\):<br />\[<br />6 - 4w = 14<br />\]<br />Subtract 6 from both sides:<br />\[<br />-4w = 8<br />\]<br />Divide by -4:<br />\[<br />w = -2<br />\]<br /><br />## Step 3: Check each value of \(w\)<br />### Now we will check if each given value of \(w\) satisfies the equation \(6 - 4w = 14\).<br /><br />1. For \(w = -5\):<br />\[<br />6 - 4(-5) = 6 + 20 = 26 \neq 14<br />\]<br />So, \(w = -5\) is not a solution.<br /><br />2. For \(w = -10\):<br />\[<br />6 - 4(-10) = 6 + 40 = 46 \neq 14<br />\]<br />So, \(w = -10\) is not a solution.<br /><br />3. For \(w = 7\):<br />\[<br />6 - 4(7) = 6 - 28 = -22 \neq 14<br />\]<br />So, \(w = 7\) is not a solution.<br /><br />4. For \(w = 4\):<br />\[<br />6 - 4(4) = 6 - 16 = -10 \neq 14<br />\]<br />So, \(w = 4\) is not a solution.