For each value of v , determine whether it is a solution to 3 v-8=2 multirow(2)(}{ v ) & multicolumn(2)(|c|)( Is it a solution? ) cline ( 2 - 3 ) & Yes & No 10 & & 0 & & 8 & & -9 & &

## Step 1: Understand the Equation<br />### We need to determine if each value of \( v \) satisfies the equation \( 3v - 8 = 2 \). This means we will substitute each value into the equation and check if it holds true.<br /><br />## Step 2: Substitute \( v = 10 \)<br />### Substitute \( v = 10 \) into the equation:<br />\[<br />3(10) - 8 = 30 - 8 = 22<br />\]<br />### Since \( 22 \neq 2 \), \( v = 10 \) is not a solution.<br /><br />## Step 3: Substitute \( v = 0 \)<br />### Substitute \( v = 0 \) into the equation:<br />\[<br />3(0) - 8 = 0 - 8 = -8<br />\]<br />### Since \( -8 \neq 2 \), \( v = 0 \) is not a solution.<br /><br />## Step 4: Substitute \( v = 8 \)<br />### Substitute \( v = 8 \) into the equation:<br />\[<br />3(8) - 8 = 24 - 8 = 16<br />\]<br />### Since \( 16 \neq 2 \), \( v = 8 \) is not a solution.<br /><br />## Step 5: Substitute \( v = -9 \)<br />### Substitute \( v = -9 \) into the equation:<br />\[<br />3(-9) - 8 = -27 - 8 = -35<br />\]<br />### Since \( -35 \neq 2 \), \( v = -9 \) is not a solution.