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}-3 x^2 y-4^2(3-x) x=-2 y=-3

Question

}-3 x^2 y-4^2(3-x) x=-2 y=-3

}-3 x^2 y-4^2(3-x) x=-2 y=-3

Solution

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DesmondAdvanced · Tutor for 1 years

Answer

### -44

Explain

## Step 1: Substitute the values of x and y<br />### Substitute $x = -2$ and $y = -3$ into the expression $-3x^2y - 4^2(3-x)$.<br />## Step 2: Simplify the expression<br />### Evaluate the exponent and the expression inside the parenthesis: $-3(-2)^2(-3) - 16(3 - (-2)) = -3(4)(-3) - 16(5)$.<br />## Step 3: Perform the multiplications<br />### Multiply the numbers: $36 - 80$.<br />## Step 4: Calculate the final result<br />### Subtract the numbers: $36 - 80 = -44$.
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