y=tanx y=cosx y=-lanx d. y=-cotx 2. (1 point) The first minimum along positive x-axis of y=2cos(3x) a. x=90^circ x=60^circ c. x=0^circ x x=180^circ

## Step 1: Analyze the given functions and identify the first minimum along the positive x-axis.<br /><br />### We are looking for the smallest positive value of $x$ for which $y = 2\cos(3x)$ reaches its minimum value. The minimum value of the cosine function is -1. Therefore, we need to find the smallest positive $x$ such that $\cos(3x) = -1$.<br /><br />## Step 2: Determine the general solution for the cosine function equal to -1.<br /><br />### The cosine function equals -1 at angles of the form $(2n+1)\pi$, where $n$ is an integer. So, we have $3x = (2n+1)\pi$.<br /><br />## Step 3: Solve for x and find the smallest positive solution.<br /><br />### Dividing both sides by 3, we get $x = \frac{(2n+1)\pi}{3}$. For $n=0$, we have $x = \frac{\pi}{3}$. Converting to degrees, $\frac{\pi}{3} = \frac{180^{\circ}}{3} = 60^{\circ}$.