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Question In Delta KLM,m=63inches,mangle K=24^circ and mangle L=42^circ Find the length of I, to the nearest inch. Answer Attemptiout of 2 l=square inches

Question

Question In Delta KLM,m=63inches,mangle K=24^circ and mangle L=42^circ Find the length of I, to the nearest inch. Answer Attemptiout of 2 l=square inches

Question
In Delta KLM,m=63inches,mangle K=24^circ  and mangle L=42^circ  Find the length of I, to the nearest
inch.
Answer Attemptiout of 2
l=square inches

Solution

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QuentinMaster · Tutor for 5 years

Answer

### 46 inches

Explain

## Step 1: Finding Angle M<br />### The sum of angles in a triangle is 180°. We have $m\angle K = 24^{\circ}$ and $m\angle L = 42^{\circ}$. Therefore, $m\angle M = 180^{\circ} - 24^{\circ} - 42^{\circ} = 114^{\circ}$.<br /><br />## Step 2: Applying the Law of Sines<br />### The Law of Sines states that $\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$. In our case, we have $\frac{l}{\sin L} = \frac{m}{\sin M}$. Substituting the known values, we get $\frac{l}{\sin 42^{\circ}} = \frac{63}{\sin 114^{\circ}}$.<br /><br />## Step 3: Solving for l<br />### We can rearrange the equation from Step 2 to solve for $l$: $l = \frac{63 \times \sin 42^{\circ}}{\sin 114^{\circ}}$. Calculating this gives $l \approx \frac{63 \times 0.6691}{0.9135} \approx 46.22$. Rounding to the nearest inch, we get $l \approx 46$ inches.
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