The absolute minimum value of f(x)=3x^2-12x+5 on the interval [0,3] ()5 -4 7 3 -7b. ( 1265(1+0.115times frac (87)/(365)))(1+0.125times (4.3)/(365))sum _(i=1)^10000i=1+2+3+ldots +10000 50005000 50500000 50050005 50005005 inftyWhat function solves the differential equation f'(x)=3x^2 y=-6x^3+C y=6x^3+C y=6x+C y=x^3+C y=-x^3+CConsider the sequence a_(n)=(3n-4)/(2n-1) Find a_(1) and a_(2) a_(1)=(2)/(3) and a_(2)=-1 a_(1)=-1 and a_(2)=(3)/(2) a_(1)=-1 and a_(2)=(2)/(3) a_(1)=1 and a_(2)=(2)/(3) a_(1)=1 and a_(2)=-(3)/(2)PREV 495051525354555657 NEXT
