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The Stefan - Boltzmann law describes the power radiated from a black body: a) S=klnW b) varepsilon =(3)/(2)kT c) R=sigma T^4 d) E=hv

Question

The Stefan - Boltzmann law describes the power radiated from a black body: a) S=klnW b) varepsilon =(3)/(2)kT c) R=sigma T^4 d) E=hv

The Stefan - Boltzmann law describes the power
radiated from a black body:
a) S=klnW
b) varepsilon =(3)/(2)kT
c) R=sigma T^4
d) E=hv

Solution

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AniyaProfessional · Tutor for 6 years

Answer

The correct answer is (c).<br /><br />The Stefan-Boltzmann law states that the total energy radiated per unit surface area of a black body per unit time (also known as the radiant emittance or radiant exitance), *R*, is directly proportional to the fourth power of the black body's absolute temperature, *T*. The constant of proportionality, *σ*, is called the Stefan-Boltzmann constant. Therefore, the equation representing the Stefan-Boltzmann law is *R* = *σT*⁴.<br />
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