A Question 19 (1 point) Retake question Calculate the change in temperature, Delta t that occurs when 12 .O kJ of thermal energy is added to 0.350 kg of water.(look in the data sheet for the specific heat capacity for water, unit conversions, do NOT include units) square A

Here's how to calculate the change in temperature:<br /><br />1. **Formula:** The formula relating heat energy (Q), mass (m), specific heat capacity (c), and change in temperature (Δt) is: Q = mcΔt<br /><br />2. **Specific Heat of Water:** The specific heat capacity of water is 4.18 kJ/kg°C (this value should be on your data sheet).<br /><br />3. **Rearrange the formula:** To solve for Δt, rearrange the formula: Δt = Q / (mc)<br /><br />4. **Plug in the values:**<br /> * Q = 12.0 kJ<br /> * m = 0.350 kg<br /> * c = 4.18 kJ/kg°C<br /><br />5. **Calculate:** Δt = 12.0 kJ / (0.350 kg * 4.18 kJ/kg°C) <br /> Δt ≈ 8.23 °C<br /><br />Therefore, the change in temperature is approximately $\boxed{8.23}$.<br />