4. If I_(balb2)=1.5mA and I_(t)=3mA determine I_(motor)

We are given that $I_{balb2} = 1.5mA$ and $I_t = 3mA$. We are asked to determine $I_{motor}$. We can assume that $I_t$ represents the total current in the circuit. If the circuit elements (bulb and motor) are in parallel, the total current is the sum of the individual branch currents.<br /><br />Therefore:<br /><br />$I_t = I_{balb2} + I_{motor}$<br /><br />We can solve for $I_{motor}$:<br /><br />$I_{motor} = I_t - I_{balb2}$<br /><br />$I_{motor} = 3mA - 1.5mA$<br /><br />$I_{motor} = 1.5mA$<br /><br />Therefore, the current through the motor is $\boxed{1.5mA}$.<br />