4. An object is experiencing an acceleration of 3.0m/s^2 while traveling in a circle at a velocity of 18.0m/s What is the radius of its motion? Formula

The formula that relates centripetal acceleration (a), velocity (v), and radius (r) of circular motion is:<br /><br />a = v²/r<br /><br />We are given:<br /><br />* a = 3.0 m/s²<br />* v = 18.0 m/s<br /><br />We need to solve for r:<br /><br />1. **Rearrange the formula:** r = v²/a<br /><br />2. **Substitute the given values:** r = (18.0 m/s)² / (3.0 m/s²)<br /><br />3. **Calculate:** r = 324 m²/s² / 3.0 m/s² = 108 m<br /><br />Therefore, the radius of the circular motion is $\boxed{108 m}$.<br />