so Two students are sitting 1.3 meters apart. One student has a mass of 62 kg. If the gravitational force between the two students is 1.08times 10^wedge 8 Newtons, what is the mass of the other student? Type square countries

Here's how to solve this problem using Newton's Law of Universal Gravitation:<br /><br />**1. The Formula:**<br /><br />Newton's Law of Universal Gravitation states:<br /><br />F = G * (m1 * m2) / r^2<br /><br />Where:<br /><br />* F is the gravitational force<br />* G is the gravitational constant (6.674 x 10^-11 N⋅m²/kg²)<br />* m1 and m2 are the masses of the two objects<br />* r is the distance between the centers of the two objects<br /><br />**2. Plug in the known values:**<br /><br />We know:<br /><br />* F = 1.08 x 10^-8 N<br />* G = 6.674 x 10^-11 N⋅m²/kg²<br />* m1 = 62 kg<br />* r = 1.3 m<br /><br />We want to find m2.<br /><br />**3. Rearrange the formula to solve for m2:**<br /><br />m2 = (F * r^2) / (G * m1)<br /><br />**4. Calculate m2:**<br /><br />m2 = (1.08 x 10^-8 N * (1.3 m)^2) / (6.674 x 10^-11 N⋅m²/kg² * 62 kg)<br /><br />m2 ≈ 44.9 kg<br /><br />**Answer:** The mass of the other student is approximately 44.9 kg.<br />