Elaine shoots a bullet straight up in the air from a gún.It reaches a height of 1940 m. How fast was the bullet fired?

Here's how to solve this problem using the principles of physics:<br /><br />**1. Understand the Concepts**<br /><br />* **Free Fall:** When the bullet reaches its maximum height, its velocity becomes zero just before it starts falling back down. We can treat this upward journey as a case of uniform deceleration due to gravity.<br />* **Equations of Motion:** We'll use the following equation of motion:<br /><br /> v² = u² + 2as<br /><br /> Where:<br /> * v = final velocity (0 m/s at the highest point)<br /> * u = initial velocity (what we want to find)<br /> * a = acceleration (in this case, -9.8 m/s² due to gravity, negative since it's acting downwards)<br /> * s = displacement (1940 m)<br /><br />**2. Solve for Initial Velocity (u)**<br /><br />* Substitute the known values into the equation:<br /><br /> 0² = u² + 2 * (-9.8 m/s²) * 1940 m<br /><br />* Simplify and solve for u:<br /><br /> 0 = u² - 38024 m²/s²<br /> u² = 38024 m²/s²<br /> u = √38024 m²/s²<br /> u ≈ 195 m/s<br /><br />**Answer:** The bullet was fired at approximately 195 m/s.<br />