4. The speed of light in carbon disulfide is 1.84times 10^8m/s Calculate the index of refraction for carbon disulfide? (4 marks)

The index of refraction (n) of a medium is defined as the ratio of the speed of light in a vacuum (c) to the speed of light in the medium (v).<br /><br />* n = c / v<br /><br />We are given:<br /><br />* v (speed of light in carbon disulfide) = 1.84 x 10⁸ m/s<br />* c (speed of light in a vacuum) = 3.00 x 10⁸ m/s (This is a fundamental constant.)<br /><br />Therefore:<br /><br />* n = (3.00 x 10⁸ m/s) / (1.84 x 10⁸ m/s)<br />* n ≈ 1.63<br /><br />So, the index of refraction for carbon disulfide is approximately $\boxed{1.63}$.<br />