6. A woman, driving a golf ball off a tee gives the ball a speed of 38m/s The mass of the ball is 0.045 kg, and the duration of the impact with the golf club is 6times 10^-3 seconds. a. What is the change in momentum of the ball? b. Determine the force applied by the club.

**a. Change in Momentum:**<br /><br />* **Initial momentum:** Before being hit, the golf ball is at rest, so its initial momentum is 0 kg⋅m/s.<br />* **Final momentum:** After being hit, the ball's momentum is calculated using the formula: momentum = mass × velocity. So, final momentum = (0.045 kg) × (38 m/s) = 1.71 kg⋅m/s.<br />* **Change in momentum:** The change in momentum is the final momentum minus the initial momentum: 1.71 kg⋅m/s - 0 kg⋅m/s = 1.71 kg⋅m/s.<br /><br />**Answer:** The change in momentum of the ball is 1.71 kg⋅m/s.<br /><br /><br />**b. Force Applied by the Club:**<br /><br />* We can use the impulse-momentum theorem, which states that the impulse (force multiplied by the time the force is applied) is equal to the change in momentum. The formula is: Impulse = Force × time = change in momentum.<br />* We know the change in momentum (1.71 kg⋅m/s) and the time of impact ($6 \times 10^{-3}$ s). We can rearrange the formula to solve for force: Force = change in momentum / time<br />* Force = (1.71 kg⋅m/s) / ($6 \times 10^{-3}$ s) = 285 N<br /><br />**Answer:** The force applied by the club is 285 N.<br />