The energy needed to melt 350 g of ice which is at 0.0^circ C is __ kJ.

Here's how to calculate the energy needed to melt the ice:<br /><br />1. **Find the latent heat of fusion for water:** The latent heat of fusion (L_f) for water is 334 J/g. This means it takes 334 joules of energy to melt 1 gram of ice at 0°C.<br /><br />2. **Calculate the total energy needed:** Multiply the mass of the ice by the latent heat of fusion:<br /><br /> Energy = mass × L_f<br /> Energy = 350 g × 334 J/g<br /> Energy = 116900 J<br /><br />3. **Convert joules to kilojoules:** Since the question asks for the answer in kJ, divide the energy in joules by 1000:<br /><br /> Energy = 116900 J / 1000 J/kJ<br /> Energy = 116.9 kJ<br /><br />Therefore, the energy needed to melt 350 g of ice at 0.0°C is $\boxed{116.9}$ kJ.<br />