12. Complete the following calculations, showing ALL UNITS AND ALL FIVE STEPS. a. A light bulb passes through a current of 0.7 A when the potential difference across the bulb is 60 V. What is the resistance of the bulb in ohms?

Here's the solution using the five-step process:<br /><br />1. **Formula:** Ohm's Law states V = IR, where V is voltage, I is current, and R is resistance. We need to rearrange this to solve for resistance (R): R = V/I<br /><br />2. **Known Values:**<br /> * V (Voltage) = 60 V<br /> * I (Current) = 0.7 A<br /><br />3. **Substitution:** Substitute the known values into the formula: R = 60 V / 0.7 A<br /><br />4. **Calculation:** Perform the division: R ≈ 85.7142857 Ω<br /><br />5. **Answer:** Rounding to a reasonable number of significant figures (likely two based on the given values), the resistance of the bulb is approximately 86 Ω (ohms).<br />