A soccer ball is kicked with an initial velocity of 36m/s at an angle of 50 degrees. What is the vertical acceleration at point B? 36(m)/(s^2) -9.8(m)/(s^2) o(m)/(s^2)

The vertical acceleration of a projectile near the Earth's surface is *always* -9.8 m/s², due to gravity. It doesn't matter what the initial velocity or angle is. Therefore, the answer is $\boxed{-9.8\frac {m}{s^{2}}}$.<br />