A 60 kg sledder starts at the top of a 52 meter hill. square square square square square square square square square square square square square square square square square square square square square square square square square square square How much potential energy does the sledder have at the top of the hill? 11.3J 30,576 J 3,120 J 1.15J

To calculate the potential energy (PE) of the sledder at the top of the hill, we can use the formula for gravitational potential energy:<br /><br />\[ PE = mgh \]<br /><br />where:<br />- \( m \) is the mass of the sledder (60 kg),<br />- \( g \) is the acceleration due to gravity (approximately 9.8 m/s²),<br />- \( h \) is the height of the hill (52 meters).<br /><br />Plugging in the values:<br /><br />\[ PE = 60 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 52 \, \text{m} \]<br /><br />\[ PE = 60 \times 9.8 \times 52 \]<br /><br />\[ PE = 30576 \, \text{J} \]<br /><br />Therefore, the potential energy of the sledder at the top of the hill is:<br /><br />\[ 30,576 \, \text{J} \]<br /><br />So, the correct answer is:<br /><br />\[ \boxed{30,576 \, \text{J}} \]