s traveling at 21.0m/s It slows to a stop at a constant rate over 5.00s How far does t during those 5.00 seconds before it stops? om 105 m 52.5 m

Here's how to solve this problem:<br /><br />**1. Identify the knowns:**<br /><br />* Initial velocity (v₀) = 21.0 m/s<br />* Final velocity (vf) = 0 m/s (since it comes to a stop)<br />* Time (t) = 5.00 s<br /><br />**2. Determine the appropriate equation:**<br /><br />Since we have constant acceleration (or deceleration in this case), we can use one of the kinematic equations. The most suitable equation is:<br /><br />d = (v₀ + vf) * t / 2<br /><br />where 'd' is the distance traveled.<br /><br />**3. Plug in the values and solve:**<br /><br />d = (21.0 m/s + 0 m/s) * 5.00 s / 2<br />d = (21.0 m/s) * 2.50 s<br />d = 52.5 m<br /><br />**Answer:** The car travels 52.5 m before stopping.<br />