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60. Two particles, each with charge +4.2mu C, exhibit a repulsive force of 0 .25 N. Calculate the distance that separates the particles.7.2) 111

Question

60. Two particles, each with charge +4.2mu C, exhibit a repulsive force of 0 .25 N. Calculate the distance that separates the particles.7.2) 111

60. Two particles, each with charge +4.2mu C, exhibit a
repulsive force of 0 .25 N. Calculate the distance that
separates the particles.7.2) 111

Solution

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BraydenMaster · Tutor for 5 years

Answer

Here's how to calculate the distance between the two charged particles:<br /><br />**1. Formula:**<br /><br />We'll use Coulomb's Law, which states:<br /><br />F = k * |q1 * q2| / r^2<br /><br />Where:<br /><br />* F is the force between the charges (0.25 N)<br />* k is Coulomb's constant (approximately 8.99 x 10^9 N m²/C²)<br />* q1 and q2 are the magnitudes of the charges (both 4.2 x 10^-6 C)<br />* r is the distance between the charges (what we want to find)<br /><br />**2. Rearrange the formula to solve for r:**<br /><br />r = sqrt(k * |q1 * q2| / F)<br /><br />**3. Plug in the values:**<br /><br />r = sqrt((8.99 x 10^9 N m²/C²) * (4.2 x 10^-6 C) * (4.2 x 10^-6 C) / (0.25 N))<br /><br />**4. Calculate:**<br /><br />r = sqrt(0.635028) m<br /><br />r ≈ 0.797 m or approximately 80 cm<br /><br />**Therefore, the distance separating the particles is approximately 0.80 meters.**<br />
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