4. Calculate the amount of energy absorbed when 45 .0 g of ice at 0.0^circ C melts. The theoretical heat of fusion of water is 6.01kJ/mol

Here's how to calculate the energy absorbed when ice melts:<br /><br />1. **Convert grams to moles:**<br /><br /> The molar mass of water (H₂O) is approximately 18.015 g/mol. Therefore:<br /><br /> Moles of ice = (45.0 g) / (18.015 g/mol) = 2.498 moles (approximately 2.50 moles)<br /><br />2. **Calculate energy absorbed:**<br /><br /> The heat of fusion tells us how much energy is needed to melt one mole of ice. We multiply the moles of ice by the heat of fusion to find the total energy absorbed:<br /><br /> Energy absorbed = (2.50 moles) * (6.01 kJ/mol) = 15.0 kJ<br /><br />**Answer:** 15.0 kJ of energy is absorbed when 45.0 g of ice at 0.0°C melts.<br />