c. How much total energy is required to actually boil 1.0 L of water in a 550 g iron pot?

To determine the total energy required to boil 1.0 L of water in a 550 g iron pot, we need to consider two main components:<br /><br />1. The energy required to heat the water from its initial temperature to its boiling point.<br />2. The energy required to heat the iron pot from its initial temperature to the boiling point of water.<br /><br />Let's assume the initial temperature of both the water and the pot is room temperature, approximately 25°C. The boiling point of water is 100°C.<br /><br />### Step 1: Calculate the energy required to heat the water<br /><br />The specific heat capacity of water is \(4.18 \, \text{J/g°C}\).<br /><br />- Volume of water = 1.0 L = 1000 mL<br />- Mass of water = 1000 g (since the density of water is approximately 1 g/mL)<br />- Temperature change for water (\(\Delta T\)) = 100°C - 25°C = 75°C<br /><br />Using the formula for heat energy:<br />\[ q_{\text{water}} = m \cdot c \cdot \Delta T \]<br /><br />\[ q_{\text{water}} = 1000 \, \text{g} \times 4.18 \, \text{J/g°C} \times 75 \, \text{°C} \]<br /><br />\[ q_{\text{water}} = 313,500 \, \text{J} \]<br /><br />### Step 2: Calculate the energy required to heat the iron pot<br /><br />The specific heat capacity of iron is \(0.45 \, \text{J/g°C}\).<br /><br />- Mass of iron pot = 550 g<br />- Temperature change for iron pot (\(\Delta T\)) = 100°C - 25°C = 75°C<br /><br />Using the formula for heat energy:<br />\[ q_{\text{iron}} = m \cdot c \cdot \Delta T \]<br /><br />\[ q_{\text{iron}} = 550 \, \text{g} \times 0.45 \, \text{J/g°C} \times 75 \, \text{°C} \]<br /><br />\[ q_{\text{iron}} = 18,562.5 \, \text{J} \]<br /><br />### Step 3: Calculate the total energy required<br /><br />Add the energy required for the water and the iron pot:<br /><br />\[ q_{\text{total}} = q_{\text{water}} + q_{\text{iron}} \]<br /><br />\[ q_{\text{total}} = 313,500 \, \text{J} + 18,562.5 \, \text{J} \]<br /><br />\[ q_{\text{total}} = 332,062.5 \, \text{J} \]<br /><br />Therefore, the total energy required to boil 1.0 L of water in a 550 g iron pot is approximately 332,063 J (or 332.1 kJ).