A Gold Medal Run Olympian Donovan Bailey took gold for his 1996 run in the 100 m event. He completed the run in just 9.84 s. From the starting blocks he accelerated at 2.34m/s^2 for 6.5 seconds. He then held this constant speed until the finish line. It was a proud Canadian moment. During Donovan Bailey's Gold medal run, what was his maximum velocity during the race? 15.2m/s 10.2m/s 18.3m/s 12.1m/s

Here's how to calculate Donovan Bailey's maximum velocity:<br /><br />* **Understand the problem:** The problem states that Bailey accelerated for 6.5 seconds and then maintained a constant velocity. This means his maximum velocity was reached at the end of the acceleration period.<br /><br />* **Use the correct formula:** We can use the following equation of motion to find his final velocity after the acceleration period:<br /><br /> v = u + at<br /><br /> Where:<br /> * v = final velocity (what we want to find)<br /> * u = initial velocity (which is 0 m/s since he starts from rest)<br /> * a = acceleration (2.34 m/s²)<br /> * t = time (6.5 s)<br /><br />* **Calculate:**<br /><br /> v = 0 + (2.34 m/s² * 6.5 s)<br /> v = 15.21 m/s<br /><br />* **Answer:** His maximum velocity during the race was approximately 15.2 m/s. Therefore, the correct answer is $\boxed{15.2 m/s}$.<br />