5. A bungee jumper is falling at a velocity of 25m/s [down] when the bungee cord just starts to stretch. After the cord stretches for 2.5 s,the velocity is 11m/s [down]. Assume that the acceleration is constant. a. What is the acceleration of the jumper?

**a. What is the acceleration of the jumper?**<br /><br />Here's how to calculate the acceleration:<br /><br />1. **Identify the knowns:**<br /><br />* Initial velocity (vᵢ) = 25 m/s [down] (We'll use positive values for downward motion)<br />* Final velocity (vₙ) = 11 m/s [down]<br />* Time interval (Δt) = 2.5 s<br /><br />2. **Choose the appropriate equation:** We can use the following equation of motion:<br /><br /> vₙ = vᵢ + aΔt<br /><br /> where 'a' is the acceleration.<br /><br />3. **Rearrange the equation to solve for acceleration (a):**<br /><br /> a = (vₙ - vᵢ) / Δt<br /><br />4. **Substitute the known values and solve:**<br /><br /> a = (11 m/s - 25 m/s) / 2.5 s<br /> a = -14 m/s / 2.5 s<br /> a = -5.6 m/s²<br /><br />Since we designated downwards as positive, the negative sign indicates the acceleration is *upwards*.<br /><br />**Answer:** The acceleration of the jumper is 5.6 m/s² [up].<br />