Question
1. An object that is 4.0 cm high and is placed 50 cm in front of a magnifying mirror with a radius of curvature of 20.0 cm. (11 marks). a. Calculate the focal length of the mirror. R=2F 20=2F 10=F 10cm b. Using formulas from this lesson, calculate: i The image location. ii. The magnification of the image. c. State two characteristics of the image that is produced.
Solution
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ThaddeusMaster · Tutor for 5 years
Answer
a. $f = 10 \, \text{cm}$ <br /><br />b.i. $\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \implies \frac{1}{10} = \frac{1}{5} + \frac{1}{d_i} \implies d_i = 10 \, \text{cm}$ <br /><br />b.ii. $M = -\frac{d_i}{d_o} \implies M = -\frac{10}{5} \implies M = -2$ <br /><br />c. The image is inverted and real.
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