Well 2 (Two Rock Chips) Chip a) The chip weighs 394.8 g dry. You first put it in a liquid that does NOT enter the pores. The liquid volume without the chip is 1,745cm^3 . The volume of liquid and chip is 1,903cm^3 You remove the chip and dry it. Then , you put it in a liquid that completely fills all the pores. The liquid volume alone is 572cm^3 The volume of liquid and chip is 713cm^3

## Step 1: Calculate the volume of Chip A<br />### The volume of the chip is the difference between the volume of the liquid and chip and the volume of the liquid alone when the liquid does *not* fill the pores. $V_{chip} = 1903 cm^3 - 1745 cm^3 = 158 cm^3$<br /><br />## Step 2: Calculate the volume of the pores in Chip A<br />### The volume of the pores is the difference between the volume of the liquid and chip and the volume of the liquid alone when the liquid *does* fill the pores. $V_{pores} = 713 cm^3 - 572 cm^3 = 141 cm^3$<br /><br />## Step 3: Calculate the porosity of Chip A<br />### Porosity is the ratio of the volume of the pores to the total volume of the chip, expressed as a percentage. $Porosity = \frac{V_{pores}}{V_{chip}} \times 100\% = \frac{141 cm^3}{158 cm^3} \times 100\% \approx 89.24\%$