Question
20) Use the Electrostatic Series to determine the charge that two neutral objects would have after they are rubbed together. If nothing happens, then state "nothing happens." [4 marks] a) Plastic is rubbed with hair. Plastic becomes __ Hair becomes __ b) Zinc is rubbed with aluminum. Zinc becomes __ Aluminum becomes __ c) Glass is rubbed with rubber Glass becomes __ Rubber becomes __ d) Of the 3 situations above, circle the letter of the materials that will produce the greatest charge difference?
Solution
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GenevieveElite · Tutor for 8 years
Answer
20)<br /><br />Here's how to determine the charges using the Electrostatic Series: The material higher on the list becomes positive (loses electrons), and the material lower on the list becomes negative (gains electrons).<br /><br />**Electrostatic Series (from positive to negative):**<br /><br />* Glass<br />* Hair<br />* Nylon<br />* Wool<br />* Fur<br />* Lead<br />* Silk<br />* Aluminum<br />* Paper<br />* Cotton<br />* Steel<br />* Rubber<br />* Nickel, Copper<br />* Brass, Silver<br />* Gold, Platinum<br />* Sulfur<br />* Acetate, Rayon<br />* Polyester<br />* Styrofoam<br />* Orlon<br />* Saran Wrap<br />* Polyurethane<br />* Polyethylene (plastic)<br />* Teflon<br /><br /><br />**a) Plastic is rubbed with hair.**<br /><br />Plastic becomes **negative**<br />Hair becomes **positive** (Hair is higher on the series than plastic)<br /><br /><br />**b) Zinc is rubbed with aluminum.**<br /><br />Zinc becomes **negative**<br />Aluminum becomes **positive** (Aluminum is higher on the series, though the difference is small, suggesting a weak charge)<br /><br /><br />**c) Glass is rubbed with rubber.**<br /><br />Glass becomes **positive**<br />Rubber becomes **negative** (Glass is significantly higher on the series than rubber)<br /><br /><br />**d) Of the 3 situations above, (c) Glass rubbed with rubber** will produce the greatest charge difference. They are farther apart on the electrostatic series than the other pairs, indicating a greater tendency for electron transfer.<br />
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