24. Suppose a 1000 -kg car collides with a tree. Its speed changes from 6m/s to 0m/s. The impuls on the car is (0.5 Points) [4 positive negative 25. A baseball catcher holds his arm straight out to catch a ball. The change in momentum on his glove is 5kgcdot m/s. The ball stops in 0.01 seconds.The initial speed of the ball is 30m/s. The force of impact is (1 Point) [4 3N 6N 150 N 500 N

**24.**<br /><br />The impulse on the car is calculated as the change in momentum:<br /><br />Impulse = Δp = mΔv = m(v_final - v_initial)<br /><br />Where:<br /><br />* m = mass of the car = 1000 kg<br />* v_final = final velocity = 0 m/s<br />* v_initial = initial velocity = 6 m/s<br /><br />Impulse = 1000 kg * (0 m/s - 6 m/s) = -6000 kg⋅m/s<br /><br />Since the impulse is negative, this indicates that the force acting on the car is in the opposite direction of its initial motion.<br /><br />**Answer:** negative<br /><br /><br />**25.**<br /><br />The force of impact can be calculated using the impulse-momentum theorem:<br /><br />Impulse = Δp = FΔt<br /><br />Where:<br /><br />* Δp = change in momentum = 5 kg⋅m/s<br />* Δt = time interval = 0.01 s<br />* F = force of impact<br /><br />We can rearrange the equation to solve for F:<br /><br />F = Δp / Δt<br /><br />F = (5 kg⋅m/s) / (0.01 s) = 500 N<br /><br />**Answer:** 500 N<br />