2. A 2000 kg helicopter moving downward with an acceleration of 4.5m/s^2 Find the applied force required and helicopter's weight required to do this. Unknowns: Fa 8 W

Here's how to solve this problem:<br /><br />**1. Understand the Forces**<br /><br />Two forces are acting on the helicopter:<br /><br />* **Weight (W):** This is the force due to gravity pulling the helicopter downwards. It's calculated as W = mg, where m is the mass and g is the acceleration due to gravity (approximately 9.8 m/s²).<br />* **Applied Force (Fa):** This is the upward force being exerted (likely by the helicopter's rotors). Since the helicopter is accelerating downwards, the weight is greater than the applied force.<br /><br />**2. Apply Newton's Second Law**<br /><br />Newton's Second Law states: F_net = ma, where F_net is the net force, m is the mass, and a is the acceleration. In this case, the net force is the difference between the weight and the applied force, and the acceleration is downwards (we'll consider downwards as positive in this case to simplify the calculation).<br /><br />So, we have: W - Fa = ma<br /><br />**3. Calculate the Weight (W)**<br /><br />W = mg = (2000 kg)(9.8 m/s²) = 19600 N<br /><br />**4. Calculate the Applied Force (Fa)**<br /><br />We know W = 19600 N, m = 2000 kg, and a = 4.5 m/s². Substitute these values into our equation from step 2:<br /><br />19600 N - Fa = (2000 kg)(4.5 m/s²)<br />19600 N - Fa = 9000 N<br />Fa = 19600 N - 9000 N<br />Fa = 10600 N<br /><br />**Answer:**<br /><br />* **Applied Force (Fa):** 10600 N upwards<br />* **Helicopter's Weight (W):** 19600 N downwards<br />