40. A nuclear power plant transmits 6.0 kA through a transmission line with a resistance of 0.50Omega . If there is a 0.70% loss of power due to transmission how much power does the nuclear plant generate? (13.6) I'm

Here's how to solve this problem:<br /><br />1. **Calculate the power loss in the transmission line:**<br /><br />Power loss (P_loss) can be calculated using the formula P_loss = I² * R, where I is the current and R is the resistance.<br /><br />* P_loss = (6000 A)² * 0.50 Ω<br />* P_loss = 18,000,000 W = 18 MW<br /><br />2. **Determine the power delivered:**<br /><br />We know that 0.70% of the total power generated is lost in transmission. This means the 18 MW represents 0.70% of the total power. Let P_total be the total power generated.<br /><br />* 0.0070 * P_total = 18 MW<br /><br />3. **Calculate the total power generated:**<br /><br />Solve for P_total:<br /><br />* P_total = 18 MW / 0.0070<br />* P_total ≈ 2571.43 MW<br /><br />Therefore, the nuclear power plant generates approximately 2571.43 MW of power.<br />