A 100 N for is applied to move a crate 25 m which encounters 37 N of friction. What is the positive amount of work done in joules?

Here's how to calculate the positive work done:<br /><br />1. **Identify the force doing positive work:** The 100 N applied force is doing positive work because it's in the same direction as the crate's displacement. The friction force does negative work.<br /><br />2. **Calculate the work done by the applied force:** Work is defined as force multiplied by displacement (in the direction of the force). So, the work done by the applied force is:<br /><br /> Work = Force x Displacement<br /> Work = 100 N x 25 m<br /> Work = 2500 Joules<br /><br />Therefore, the positive amount of work done is $\boxed{2500}$ Joules.<br />