a. Draw the following the dirention of electron in using circuit diagrams Lahel all the components current AT EAC A POWER SOURCE In both elrouits. a A series circuit with two 9 V cells, a single light built offering 15 ohme resistance, and a single resistor offering 10 ohme of resistance. (5)marks)

Here's the diagram and breakdown for a series circuit with two 9V cells, a 15-ohm light bulb, and a 10-ohm resistor:<br /><br />**Diagram:**<br /><br />```<br /> +---(9V)---(9V)---+---/\/\/\/\---/\/\/\/\---+<br /> | | 15Ω 10Ω |<br /> +--------------------------------------------+<br />```<br /><br />**Components and Labels:**<br /><br />* **(9V):** Two 9V battery cells. Since they are in series, their voltages add. The total voltage supplied to the circuit is 18V (9V + 9V).<br />* **15Ω:** The light bulb with a resistance of 15 ohms. The symbol /\/\/\/\ represents a resistor, and in this case, it's the resistance offered by the light bulb's filament.<br />* **10Ω:** A resistor with a resistance of 10 ohms. Again, /\/\/\/\ represents the resistor.<br />* **Wires:** The lines connecting the components. These are assumed to have negligible resistance.<br />* **Series Connection:** All components are connected in a single loop. This means the same current flows through each component.<br /><br />**Key Concepts in a Series Circuit:**<br /><br />* **Current (I):** The current is the same at every point in a series circuit.<br />* **Voltage (V):** The total voltage across the circuit is equal to the sum of the individual voltage drops across each component.<br />* **Resistance (R):** The total resistance in a series circuit is equal to the sum of the individual resistances.<br /><br />**Calculations (Optional - not requested in the question, but helpful for understanding):**<br /><br />* **Total Resistance (R_T):** R_T = 15Ω + 10Ω = 25Ω<br />* **Total Current (I):** Using Ohm's Law (V = IR), I = V/R = 18V / 25Ω = 0.72 Amperes<br />* **Voltage drop across the light bulb (V_bulb):** V_bulb = I * R_bulb = 0.72A * 15Ω = 10.8V<br />* **Voltage drop across the resistor (V_resistor):** V_resistor = I * R_resistor = 0.72A * 10Ω = 7.2V<br /><br /><br />This diagram and explanation fulfill the requirements of the question, showing a series circuit with the specified components labeled correctly. The additional calculations illustrate how the circuit would behave in a real-world scenario.<br />