PRC4A17-A1-7-2 -11 The coefficient of friction between a block and a horizontal surface is 0.290 Determine the mass of the block if a force of 950.000 N is required to keep it sliding alcing the surface. square A

Here's how to solve this problem:<br /><br />**1. Understand the concept of friction:**<br /><br />The force of friction (F_f) acting on an object sliding on a surface is given by:<br /><br />F_f = μ * N<br /><br />Where:<br /><br />* μ is the coefficient of friction<br />* N is the normal force (the force perpendicular to the surface)<br /><br />**2. Determine the normal force:**<br /><br />Since the block is on a horizontal surface, the normal force (N) is equal to the weight (W) of the block:<br /><br />N = W = m * g<br /><br />Where:<br /><br />* m is the mass of the block<br />* g is the acceleration due to gravity (approximately 9.8 m/s²)<br /><br />**3. Relate the applied force to the force of friction:**<br /><br />The problem states that a force of 950 N is required to *keep* the block sliding. This means the applied force is equal to the force of friction:<br /><br />F_applied = F_f<br /><br />**4. Solve for the mass:**<br /><br />Now we can put everything together:<br /><br />F_applied = F_f = μ * N = μ * m * g<br /><br />We are given:<br /><br />* F_applied = 950 N<br />* μ = 0.290<br />* g = 9.8 m/s²<br /><br />We need to solve for m:<br /><br />m = F_applied / (μ * g)<br /><br />m = 950 N / (0.290 * 9.8 m/s²)<br /><br />m ≈ 335.6 kg<br /><br />**Answer:**<br /><br />The mass of the block is approximately 335.6 kg.<br />