A7 mbar is pivoted at 2 m from the left end.Aforce of 60 N is applied downwardly on the left end and a force of 20 N is applied downwardly on the right end. What would be the clockwise and counter -clockwise moments and in which direction would the bar rotate? (a) 80 Nm counter -clockwise, 100 Nm clockwise counter-clockwise rotation (b) 60 Nm counter -clockwise, 100 Nm clockwise clockwise rotation (c) 120 Nm counter -clockwise, 100 Nm clockwise counter-clockwise rotation (d) 120 Nm counter-clockwise 100 Nm clockwise, clockwise rotation

Here's how to solve this problem and determine the rotation:<br /><br />**1. Calculate the Counter-Clockwise Moment:**<br /><br />* The 60 N force on the left end creates a counter-clockwise moment.<br />* Moment = Force x Distance from pivot<br />* Counter-clockwise moment = 60 N * 2 m = 120 Nm<br /><br />**2. Calculate the Clockwise Moment:**<br /><br />* The 20 N force on the right end creates a clockwise moment.<br />* We need to find the distance of this force from the pivot. Since the bar is 7 m long and the pivot is 2 m from the left end, the right end is 7 m - 2 m = 5 m from the pivot.<br />* Clockwise moment = 20 N * 5 m = 100 Nm<br /><br />**3. Determine the Net Moment and Rotation:**<br /><br />* The counter-clockwise moment is 120 Nm, and the clockwise moment is 100 Nm.<br />* Since the counter-clockwise moment is greater, the bar will rotate counter-clockwise.<br />* Net moment = 120 Nm (counter-clockwise) - 100 Nm (clockwise) = 20 Nm counter-clockwise<br /><br />**Therefore, the correct answer is (c) 120 Nm counter-clockwise, 100 Nm clockwise, counter-clockwise rotation.**<br />