1. 18 C of charge pass a certain point in a conductor in 2.5 s a) What is the current in the wire? b) How many electrons have passed that point in the wire in 2.5 s? a) exists =(Q)/(t)=(18C)/(2.55)=7.24

1. 18 C of charge pass a certain point in a conductor in 2.5 s<br /><br />a) What is the current in the wire?<br /><br />Current (I) is defined as the rate of flow of charge (Q) with respect to time (t). The formula is:<br /><br />I = Q / t<br /><br />Where:<br /><br />* I is the current in Amperes (A)<br />* Q is the charge in Coulombs (C)<br />* t is the time in seconds (s)<br /><br />In this case, Q = 18 C and t = 2.5 s. Therefore:<br /><br />I = 18 C / 2.5 s = 7.2 A<br /><br />So, the current in the wire is 7.2 Amperes.<br /><br />b) How many electrons have passed that point in the wire in 2.5 s?<br /><br />We know that the charge of a single electron (e) is approximately -1.6 x 10⁻¹⁹ C. To find the number of electrons (n) that have passed a point, we can use the following formula:<br /><br />Q = n * e<br /><br />Where:<br /><br />* Q is the total charge in Coulombs (C)<br />* n is the number of electrons<br />* e is the elementary charge (1.6 x 10⁻¹⁹ C)<br /><br />We can rearrange the formula to solve for n:<br /><br />n = Q / e<br /><br />Substituting the values:<br /><br />n = 18 C / (1.6 x 10⁻¹⁹ C) <br />n = 1.125 x 10²⁰ electrons<br /><br />So, approximately 1.125 x 10²⁰ electrons have passed that point in the wire in 2.5 seconds.<br />