A 800kg car, traveling 16m/s to the right collides with a 3000kg semi truck initially at rest. After the 07s collision, the semi truck ends up moving 5.8m/s m/s right. vert Jvert =square unit before collision: P_(car)=square unit P_(truck)=square unit after collision: P_(car)=square unit P_(truck)=square unit What direction did the car move after the collision? square How fast did the car move after the collision? square square v What was the magnitude of the average impact force? square square

Here's the solution:<br /><br />**1. Impulse:**<br /><br />The impulse ($\vert J\vert$) is the change in momentum of the truck (since it started from rest).<br /><br />* Impulse = change in momentum of the truck<br />* $\vert J\vert = m_{truck} * \Delta v_{truck}$<br />* $\vert J\vert = 3000 kg * 5.8 m/s$<br />* $\vert J\vert = 17400 kg*m/s$<br /><br />**$\vert J\vert = 17400$ kg*m/s**<br /><br />**2. Momentum Before Collision:**<br /><br />* $P_{car} = m_{car} * v_{car} = 800 kg * 16 m/s = 12800 kg*m/s$<br />* $P_{truck} = m_{truck} * v_{truck} = 3000 kg * 0 m/s = 0 kg*m/s$<br /><br />**$P_{car} = 12800$ kg*m/s**<br />**$P_{truck} = 0$ kg*m/s**<br /><br />**3. Momentum After Collision:**<br /><br />* $P_{truck} = m_{truck} * v_{truck} = 3000 kg * 5.8 m/s = 17400 kg*m/s$<br />* To find the car's momentum after the collision, we use the principle of conservation of momentum:<br /> * Total momentum before = Total momentum after<br /> * $P_{car-before} + P_{truck-before} = P_{car-after} + P_{truck-after}$<br /> * $12800 kg*m/s + 0 kg*m/s = P_{car-after} + 17400 kg*m/s$<br /> * $P_{car-after} = 12800 kg*m/s - 17400 kg*m/s = -4600 kg*m/s$<br /><br />**$P_{car} = -4600$ kg*m/s**<br />**$P_{truck} = 17400$ kg*m/s**<br /><br />**4. Car's Direction After Collision:**<br /><br />The negative sign on the car's momentum indicates it's moving in the opposite direction to its initial motion.<br /><br />**Left**<br /><br />**5. Car's Speed After Collision:**<br /><br />* $P_{car-after} = m_{car} * v_{car-after}$<br />* $-4600 kg*m/s = 800 kg * v_{car-after}$<br />* $v_{car-after} = -4600 kg*m/s / 800 kg = -5.75 m/s$<br />* The speed is the absolute value of the velocity.<br /><br />**5.75 m/s**<br /><br />**6. Magnitude of Average Impact Force:**<br /><br />* Impulse = Force * time<br />* $\vert J\vert = F_{avg} * t$<br />* $17400 kg*m/s = F_{avg} * 0.7 s$<br />* $F_{avg} = 17400 kg*m/s / 0.7 s = 24857.14 N$<br /><br />**24857.14 N** (or approximately 24900 N depending on significant figures)<br />