The temperature of 12.0 g of an unknown substance was raised approximatelx 150^circ C i J of heat energy was added. Identify the substance based on the experimental calculatio heat capacity. (A) glass B. aluminium e. iron A. copper

To identify the substance based on its specific heat capacity, we need to use the formula for calculating heat energy:<br /><br />\[ q = m \cdot c \cdot \Delta T \]<br /><br />where:<br />- \( q \) is the heat energy added (in joules),<br />- \( m \) is the mass of the substance (in grams),<br />- \( c \) is the specific heat capacity (in J/g°C),<br />- \( \Delta T \) is the change in temperature (in °C).<br /><br />Given:<br />- \( m = 12.0 \, \text{g} \)<br />- \( \Delta T = 150^{\circ}C \)<br /><br />We are not given the exact amount of heat energy (\( q \)), so let's assume a hypothetical value or that it was omitted by mistake. For this example, let's assume \( q = 1800 \, \text{J} \) as an arbitrary value for calculation purposes.<br /><br />Rearranging the formula to solve for the specific heat capacity (\( c \)):<br /><br />\[ c = \frac{q}{m \cdot \Delta T} \]<br /><br />Substitute the values:<br /><br />\[ c = \frac{1800 \, \text{J}}{12.0 \, \text{g} \times 150^{\circ}C} \]<br /><br />\[ c = \frac{1800}{1800} \]<br /><br />\[ c = 1.0 \, \text{J/g°C} \]<br /><br />Now, compare this calculated specific heat capacity with the known specific heat capacities of the substances:<br /><br />- Glass: approximately 0.84 J/g°C<br />- Aluminium: approximately 0.897 J/g°C<br />- Iron: approximately 0.450 J/g°C<br />- Copper: approximately 0.385 J/g°C<br /><br />Based on the approximate calculation, the closest match to 1.0 J/g°C would be glass. Therefore, the substance is most likely:<br /><br />(A) glass