RC4A/17-A1-2-2 -22 A crowbar is 3 metres long and has its pivot 30 cm from one and.A force of 3000 N is applied to the end closest to the pivot. What effort must se applied to the other end of the crowbar to keep it in equilibrium: 333.3 N 300.0 N 250.N 27778 N

Here's how to solve this lever problem:<br /><br />**1. Understand the Principle of Levers:**<br /><br />A lever is in equilibrium when the moment (torque) on one side of the pivot equals the moment on the other side. The moment is calculated as the force applied multiplied by the distance from the pivot.<br /><br />**2. Convert Units:**<br /><br />Keep all units consistent. The crowbar is 3 meters long, and the pivot is 30 cm from one end. Convert 30 cm to meters: 30 cm * (1 m / 100 cm) = 0.3 m<br /><br />**3. Determine Lever Arm Lengths:**<br /><br />* **Effort Arm:** The distance from the pivot to where the effort is applied (the longer end) is 3 m - 0.3 m = 2.7 m<br />* **Load Arm:** The distance from the pivot to where the load (3000 N force) is applied is 0.3 m<br /><br />**4. Set up the Equilibrium Equation:**<br /><br />Effort * Effort Arm = Load * Load Arm<br /><br />Let 'E' represent the effort force:<br /><br />E * 2.7 m = 3000 N * 0.3 m<br /><br />**5. Solve for Effort (E):**<br /><br />E = (3000 N * 0.3 m) / 2.7 m<br />E = 900 Nm / 2.7 m<br />E = 333.33 N (approximately)<br /><br />**Answer:**<br /><br />The effort required is approximately 333.3 N. Therefore, the closest answer among the choices is 333.3 N.<br />