EXERCICE 1 DOCUMENT DE RÉVISION GÉOMÉTRIE Voici un solide troué.Sachant que le diamètre des cylindres est de 0,2 mètre, quelle est la capacité, en litres, de ce solide?

Here's how to calculate the volume (and therefore the capacity) of the hollowed solid:<br /><br />1. **Calculate the volume of the large cylinder:**<br /><br />* **Radius:** The diameter is 0.2 meters, so the radius is 0.2 m / 2 = 0.1 m.<br />* **Height:** We need the height of the large cylinder. The diagram doesn't provide this information. Let's call the height of the large cylinder "h" meters.<br />* **Volume:** The volume of a cylinder is πr²h. So the large cylinder's volume is π * (0.1 m)² * h = 0.01πh m³<br /><br />2. **Calculate the volume of the small cylinder (the hole):**<br /><br />* **Radius:** The diameter is 0.2 meters, so the radius is 0.2 m / 2 = 0.1 m.<br />* **Height:** We need the height of the smaller cylinder. Again, the diagram doesn't give us this. Let's call the height of the small cylinder "h_small" meters. It's important to note that h_small must be less than or equal to h.<br />* **Volume:** The volume of the small cylinder is π * (0.1 m)² * h_small = 0.01πh_small m³<br /><br />3. **Calculate the volume of the solid:**<br /><br />* **Subtract:** The volume of the solid is the volume of the large cylinder minus the volume of the small cylinder: 0.01πh m³ - 0.01πh_small m³ = 0.01π(h - h_small) m³<br /><br />4. **Convert to liters:**<br /><br />* **Cubic meters to liters:** 1 m³ = 1000 liters.<br />* **Final Calculation:** The capacity in liters is 0.01π(h - h_small) m³ * 1000 liters/m³ = 10π(h - h_small) liters.<br /><br />**Therefore, the capacity of the solid is 10π(h - h_small) liters, where 'h' is the height of the large cylinder and 'h_small' is the height of the smaller cylinder (the hole). You need to provide the values of 'h' and 'h_small' to get a numerical answer.**<br />