14. A high-speed windmill can utilize a maximum wind power of 6.53times 10^3 W. If the windmill turned a generator that was only 27.0% efficient, the actual electrical power output is a.bctimes 10^dW The values of a b, c and d are __ __ __ and __ (Record your answer in the numerical-response section below.) Your answer: square square square square

To find the actual electrical power output of the windmill, we need to calculate 27.0% of the maximum wind power it can utilize.<br /><br />Given:<br />- Maximum wind power = \(6.53 \times 10^3\) W<br />- Efficiency of the generator = 27.0%<br /><br />The actual electrical power output is calculated as follows:<br /><br />\[<br />\text{Actual Power Output} = \text{Maximum Wind Power} \times \text{Efficiency}<br />\]<br /><br />\[<br />\text{Actual Power Output} = 6.53 \times 10^3 \times \frac{27.0}{100}<br />\]<br /><br />\[<br />\text{Actual Power Output} = 6.53 \times 10^3 \times 0.27<br />\]<br /><br />\[<br />\text{Actual Power Output} = 1.7631 \times 10^3 \, \text{W}<br />\]<br /><br />Now, express this in the form \(a.bc \times 10^d\):<br /><br />- \(a = 1\)<br />- \(b = 7\)<br />- \(c = 6\)<br />- \(d = 3\)<br /><br />Therefore, the values of \(a\), \(b\), \(c\), and \(d\) are 1, 7, 6, and 3 respectively.<br /><br />Your answer: \(1 \, 7 \, 6 \, 3\)