6. In an emergency , a car is also required to stop in 1 second (it was travelling 10m/s) . If the car has a mass of 1000kg, how much force must the brakes apply to stop the vehicle?

Here's how to calculate the force required:<br /><br />1. **Calculate the acceleration:** The car goes from 10 m/s to 0 m/s in 1 second. Acceleration (or in this case, deceleration) is the change in velocity divided by the change in time.<br /><br /> Acceleration (a) = (Final velocity - Initial velocity) / Time<br /> a = (0 m/s - 10 m/s) / 1 s<br /> a = -10 m/s² (The negative sign indicates deceleration)<br /><br />2. **Apply Newton's Second Law:** Force (F) equals mass (m) times acceleration (a).<br /><br /> F = m * a<br /> F = 1000 kg * -10 m/s²<br /> F = -10,000 N<br /><br />Therefore, the brakes must apply a force of $\boxed{10,000 N}$ to stop the vehicle. The negative sign indicates the force is in the opposite direction of the car's motion.<br />