Perform the calculations to the correct number of significant figures. 1.10times 0.5120times 4.0015div 3.4555= A 0.6522 B 0.65 C 0.65219 D 0.652 Question 8 A sick child has a temperature of 40.00^circ C What is the child's temperature inKelvin? A 633.15 K B 273.15K C 233.15 K D 313.15 K

**Question 7:**<br /><br />1. **Multiplication and Division with Significant Figures:** When multiplying and dividing, the result should have the same number of significant figures as the measurement with the *fewest* significant figures.<br /><br />2. **Calculation:** $1.10 \times 0.5120 \times 4.0015 \div 3.4555 = 0.652189...$<br /><br />3. **Significant Figures:**<br /> * 1.10 has three significant figures.<br /> * 0.5120 has four significant figures.<br /> * 4.0015 has five significant figures.<br /> * 3.4555 has five significant figures.<br /><br /> The fewest number of significant figures is three (from 1.10).<br /><br />4. **Rounding:** We round the calculated value (0.652189...) to three significant figures, which gives us 0.652.<br /><br />**Answer:** D. 0.652<br /><br /><br />**Question 8:**<br /><br />1. **Celsius to Kelvin Conversion:** To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature.<br /><br />2. **Calculation:** $40.00^{\circ}C + 273.15 = 313.15 K$<br /><br />**Answer:** D. 313.15 K<br />